-(x^2-8x+48)=0

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Solution for -(x^2-8x+48)=0 equation:


Simplifying
-1(x2 + -8x + 48) = 0

Reorder the terms:
-1(48 + -8x + x2) = 0
(48 * -1 + -8x * -1 + x2 * -1) = 0
(-48 + 8x + -1x2) = 0

Solving
-48 + 8x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
48 + -8x + x2 = 0

Move the constant term to the right:

Add '-48' to each side of the equation.
48 + -8x + -48 + x2 = 0 + -48

Reorder the terms:
48 + -48 + -8x + x2 = 0 + -48

Combine like terms: 48 + -48 = 0
0 + -8x + x2 = 0 + -48
-8x + x2 = 0 + -48

Combine like terms: 0 + -48 = -48
-8x + x2 = -48

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -48 + 16

Reorder the terms:
16 + -8x + x2 = -48 + 16

Combine like terms: -48 + 16 = -32
16 + -8x + x2 = -32

Factor a perfect square on the left side:
(x + -4)(x + -4) = -32

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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